Giannis Antetokounmpo and the Milwaukee Bucks are having a good start to their 2025-26 NBA season. While their record isn’t spotless, having already lost a game to the Cleveland Cavaliers last Sunday on the road, the Bucks hold a 3-1 slate following a bounce-back 121-111 win at home over the New York Knicks on Tuesday.
Antetokounmpo looked unstoppable in that contest. The Greek Freak erupted for 37 points, making 16 of his 22 attempts from the field. He added eight rebounds and seven assists with two blocks and a steal for another great individual night. But Antetokounmpo and the Bucks will have a tough assignment up next, as Milwaukee is scheduled to host the red-hot Golden State Warriors at Fiserv Forum this Thursday
The Warriors are 4-1 through five games, and are coming off a 98-79 victory against the Los Angeles Clippers in San Francisco last Tuesday.
Giannis Antetokounmpo among long-tenured players in Bucks-Warriors
Apart from two legitimate NBA title contenders colliding in Milwaukee this Thursday, the game will also feature three players who have been in the league for over a decade but have not played for a team outside of the ones that drafted them.
Via Bucks Realm:
Thursday’s Bucks Warriors matchup will feature the league’s three longest-tenured players with a single franchise:
Stephen Curry (17 years)
Draymond Green (14 years)
Giannis Antetokounmpo (13 years)
Antetokounmpo has been with the Bucks from the start. He was taken by Milwaukee 15th overall in the first round of the 2013 NBA Draft. On the side of the Warriors, Curry arrived in the league in 2019 as the Warriors’ first-round pick (seventh overall). As for Green, he entered the NBA in 2012 after Golden State took him in the second round (35th overall) of that year’s draft.
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